Essay by reason of me
QLT 1: Task 5
A1.
Ryan has started a strange job in downtown Atlanta. He is looking at various options for parking his vehicle for the period of the workweek. He has narrowed it from the top to the bottom of to two options, a parking garage oblation a flat rate of $30 dollars a month and a different garage slightly further away which charges 0.15 by means of hour.
A2.
Ryan just recently moved to Atlanta in the place of this new job opportunity. Taking into notice the financial impact the move has created in the same state as purchasing a new place, of recent origin furniture, and all necessary necessities, it power of determination be critical he find the cheapest option for parking.
A3.
The first cost option is parking garage A, what one. features a monthly unlimited parking lapse for $30 dollars a month.
The encourage option is parking garage B, which is slightly further away from his job but charges 0.15 a twenty-fourth part of a day.
B1.
To determine the best cost effective parking option we will stand in want of to determine which offers the most excellent rates. A standard 8 hour work day will be used to fix upon how many hours per day to charge. a = Number of days, x = Total cost.
Parking garage A - (a - a) + 30 = x
Parking garage B - (0.15 x 8) a = x
B2.
Parking Garage A command be charged a flat rate unconcerned of how many days it is used. Thus having the days expunge out so the flat 30 dollars is harmonious across the month is needed to bear a comparison the relationship of parking garage B.
Parking Garage B from the time of it is a hourly rate be inclined need to take into account the colors work day of 8 hours at that time determine how many days per month it will be used.
B3.
To have a distinct assessment we will need to employment a maximum length of 31 days in a month. This second nature the hourly parking garage is assessed fairly if overtime or if Ryan is called into operate extra throughout the month.
Parking Garage A - (31 - 31) + 30 = x Parking Garage A - (1 - 1) + 30 = x
0 + 30 = x...
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