Essay very lately
Restitution Lab
Aim: Find the coefficient of compensation.
Materials: The materials we used were a meterstick, golf round, ping-pong ball, softball, tennis ball and a sparkly super ball.
Procedure: Ginzy and I dropped the softball from a elevation of 1 meter and noted which height the ball bounced back to we did this five seasons for each ball all the space of time recording the results. We then used the equation (h/H)= Coefficient of satisfaction and recorded our answers.
Observations: Some balls bounced higher than others.
The Coefficient of restoration was different for each ball.
Sketch:
Data:
Object H (cm) h1 (cm) h2 (cm) h3 (cm) h4 (cm) h5 (cm) havg (cm) c.o.r.
Softball 100 20 25 24 27 23 23.8 0.49
Golf round 100 55 54 60 46 56 54.2 0.74
Tennis round 100 49 53 50 52 50 50.8 0.71
Ping-pong sphere 100 57 59 61 57 60 58.8 0.77
Sparkly super round 100 74 77 74 76 77 75.6 0.87
Concluding Questions:
1. This lab obeys the mosaic code of conservation of energy because in ~ degree energy disappears it simply changes forms.
2. What veritably happened to the PE that was “perplexed” was that it was converted into warm energy when the ball hit the get a~ due to the friction between the ball and the ground.
3. An application for a low coefficient of indemnification would be a truck hitting a tree while an application for a high coefficient of indemnification would be a super ball or considered in the state of popularly referred to as a bouncy sphere.
4. The theoretical value of the coefficient of repayment in a perfectly elastic collision would have ~ing 1 this is because in every elastic collision no KE is depraved and therefore the speed before the collision and speed after the collision are the similar making the coefficient of restitution equivalent; of the same extent 1 (since the coefficient of restoration=speed before collision/speed after crash).
Extra credit: Balls bounce due to the liberate of compression.
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