Quadratic Essay

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f(x)= 2x^2 + 8x + 5

Vertex: In canon to find the vertex of the quadratic equation, break ground by using the proper formula - b / 2(a) to discover it. In the equation there is every (a) (b) (c) which is needed by reason of the vertex equation. First look at the equation and fix upon what are the values of the three shifting. In this case (a)= 2, (b)= 8, (c)= 5. Now quid them in properly into the top equation. * Notice in the vertex equation in that place is a negative sign!!! DO NOT FORGET! When plugged into the equation, it should pass -8 / 2(2). Now use the particular steps and multiply the denominator through 2 as it implies resulting the denominator equalling 4. Now the summit equation should be (-8 / 4) more reducing would make it (-2). The (x) utility of the vertex (-2, 0). To determine judicially the (y) value plug in the x-vertex back into the original equation f (x)= 2x^2+8x+5, resulting to have ~ing f(x)= 2(-2)^2+8(-2)+5. Use the family of operation (PEMDAS) to solve. * Do not overlook that the exponent (^2) gets many into (-2) not the product of 2(-2). After using those steps the f(x) or (y) esteem should equal -3, making the vertex (-2, -3).

x-intercept: The aid step is finding the x-interrupt (zeros, roots). Begin by using the quadratic ~ry to find the x-intercept. As regular in the process of finding the zenith, use the same variables and values (a)= 2, (b)= 8, (c)= 5. Plug in the values into the equation

Using the similar order of operation it should have ~ing

then reduce,

Now to find the epigram make

add and subtract and

equalling (.75 , -3.75).

Graphing: Having the crown of the head point and the x-intercept points from the quadratic equation chew in the results into a graphing calculator to repression if the answers are correct. Check whether or not your vertex point (-2, -3) and x-intercepts (.75, -3.25) oppose to your graph.

* points of the x-seize on the passage fall on the x-axis creating a parabola graph.

  
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